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Unformatted text preview: Solving for the wavelength, we have 5100 m s 12.8 m 400 Hz v f λ = = = 24. This rope has one free end and one fixed end. Because the distance between adjacent nodes and antinodes is onefourth the wavelength, the fundamental wavelength is four times the length of the rope, or 12 m long. Drawings show that this rope only has the odd harmonics, so the wavelengths are 12 12 12 12 m, m, m, m, . .. 1 3 5 7 λ =...
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This document was uploaded on 10/29/2011 for the course PHSX 103 at MSU Bozeman.
 Fall '02
 GregoryFrancis

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