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Unformatted text preview: Solving for the wavelength, we have 5100 m s 12.8 m 400 Hz v f λ = = = 24. This rope has one free end and one fixed end. Because the distance between adjacent nodes and antinodes is one-fourth the wavelength, the fundamental wavelength is four times the length of the rope, or 12 m long. Drawings show that this rope only has the odd harmonics, so the wavelengths are 12 12 12 12 m, m, m, m, . .. 1 3 5 7 λ =...
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This document was uploaded on 10/29/2011 for the course PHSX 103 at MSU Bozeman.
- Fall '02