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Unformatted text preview: cut in half. Exercises 16. We known that the measured frequencies for the guitar string must be integer multiples of the lowest, or fundamental, frequency. Therefore, the fundamental frequency must be 150 Hz and these frequencies correspond to the 4 th , 5 th , and 6 th harmonics, respectively. 20. An open organ pipe is open at both ends. The fundamental wavelength is twice the length of the tube. Therefore, 1 2 2.4 m L = = and the fundamental frequency can be calculated from the wave equation 1 1 343 m s 143 Hz 2.4 m v f = = = This pipe has all harmonics, so 2 1 2 283 Hz f f = = 3 1 3 429 Hz f f = = 4 1 4 572 Hz, and so on f f = =...
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 Fall '02
 GregoryFrancis

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