sol24 - The bulb in arrangement (c) is the brightest...

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PHYSICS 103 Chapter 21 -- HW #24 Questions 2. The size of the cell does not change the voltage but it does change the length of time the battery can supply current. The larger the cell, the longer the current lasts. 8. We have to be a little careful with this question. In arrangement (d), the batteries are wired in series but the batteries oppose each other. Therefore, the bulbs do not light. In arrangement (b), the batteries are wired in parallel but one of the batteries is backward. Therefore, the current loops around through the batteries and does not pass through the bulb. These two possibilities are eliminated because the bulbs are not lit. The brightness of the bulb in arrangement (a) is the same as our standard because the batteries are wired in parallel and provide the same voltage as a single battery.
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Unformatted text preview: The bulb in arrangement (c) is the brightest because the batteries are wired in series and the voltage is twice the voltage of a single battery. Exercises 2. We solve this exercise using Ohms law. 120 V 8 15 A V R I = = = If the resistance is lower than 8 , the current will be even larger than 15 A. 8. We first need to realize that connecting two batteries in parallel does not increase the voltage. Therefore, the voltage is 1.5 V. We now use Ohms law to find the current through the resistor. 1.5 V 0.5 A 3 V V R I I R = = = = Because the batteries are connected in parallel, half the current flows through each battery. Therefore, the current through each battery is 0.25 A....
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This document was uploaded on 10/29/2011 for the course PHSX 103 at MSU Bozeman.

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