sol25 - You get the least resistance by wiring the two...

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PHYSICS 103 Chapter 20 -- HW #25 Questions 28. Adding anything in series with an existing circuit decreases the current through the battery because the total resistance of the circuit increases. 32. We learned in lab that adding a bulb in series with a single bulb connected to a battery causes the single bulb to decrease in brightness. This “less glow” indicates that there is less flow, which means that there is more resistance in the circuit. On the other hand, adding a bulb in parallel with a single bulb leaves the single bulb with the same brightness. Because each bulb has the “standard brightness,” there must be twice as much current, which means that there is less resistance. Therefore, the two bulbs in series offer the greater resistance. 42. You get the most voltage by wiring the two batteries in series.
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Unformatted text preview: You get the least resistance by wiring the two bulbs in parallel. Therefore, batteries in series and bulbs in parallel produces the most light. 48. Unscrewing bulb A breaks the circuit. Therefore, bulb A must be wired in series with the combination of bulbs B and C. This is confirmed by the observation that unscrewing bulbs B and C also breaks the circuit. Bulbs B and C must be wired in parallel as unscrewing either one produces the same effect in the other. We also note that unscrewing either bulb B or bulb C seems to put the other bulb in series with bulb A. Thus, bulbs B and C are in parallel with each other and the combination is in series with bulb A. The bulbs are wired like the circuit in Figure 21-12....
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This document was uploaded on 10/29/2011 for the course PHSX 103 at MSU Bozeman.

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