salts - • Kb = [OH-] [lactic acid] / [lactate] • [OH-]...

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conjugate acid-base pairs  - HX + H2O >> X- + H3O+   HX is acid o conjugate acid of X- (add proton) H2O acts as base o conjugate base of H3O+ (subtract proton) X- is base o conjugate base of HX (subtract proton) H3O+ acts as acid o conjugate acid of H2O (add proton) conjugate acid of strong base = weak acid conjugate acid of weak base = strong acid conjugate base of strong acid = weak base conjugate base of weak acid = strong base Ka x Kb = Kw o Kw = 1.0 x 10-14 (water autoionizes) o Ka = Kb >> neutral solution Find the pH for 0.25 M of sodium lactate   conjugate acid is lactic acid Ka of lactic acid = 1.4 x 10-4 Kb = Kw / Ka = 10-14 / (1.4 x 10-4) = 7.14 x 10-11
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Unformatted text preview: • Kb = [OH-] [lactic acid] / [lactate] • [OH-] = [(7.14 x 10-11) (0.25)]1/2 = 4.2 x 10-6 • pOH = -log [OH-] = 5.37 • pH = 14 - 5.37 = 8.63 hydrolysis - ability of ions to react w/ water to make H+, OH- ions • anions act as bases (adding proton >> acid) o identify conjugate acid, use Kw to find the strength o anions of strong acids have negligible effect o anions of weak acids increase pH • cations act as acids (subtract proton >> base) o identify conjugate base, use Kw to find the strength o cations of strong bases have negligible effect o cations of weak bases decrease pH...
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This document was uploaded on 10/30/2011 for the course CHEM 161 at Rutgers.

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