Business Calc Homework w answers_Part_57

1 3x e 3 1 2 3x 2 1 1 xe xe 3x e 3x dx 3 3 3 3 1 2 3x

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Unformatted text preview: os x 3e 3x sin x] 10 3 sin x cos x 3x e C 10 10 e 3x sin x dx x 2e 3x dy dt 1 t 4 1 dy v t dy y dt 4 1 t ln t 4 dt 4 y ( 3) C ln (1) C ln (t 2 2 y C 4) 2 Graphical Support: x2 1x 2 x2 dy 1x dx 2 2 x dy 1x dx 2 12 13 yx x x C 2 6 dy 21. dx y (0) y C x3 6 x 24. dy d csc 2 cot 2 dy 1 x2 2 [ 4.5, 5] by [ 2, 5] csc 2 cot 2 d 1 dy csc 2 cot 2 d Graphical support: 1 csc 2 C 2 1 C1 2 y y C [ 4, 4] by [ 3, 3] y 4 3 2 1 csc 2 2 3 2 [0, 1.57] by [ 5, 3] 1 3 283 Chapter 6 Review d(y ) dx 25. d (y ) d (y ) x2 y y (1) x 2 1 C 26. d(r ) dt cos t d (r ) 1 x2 1 2x dx x2 1 2x dx x2 2x cos t dt d (r ) cos t dt r C r (0) 1 sin t C r C sin t d(r ) y (1) 2 3 C C y x (x 2 dy y 1 1 1 x r 1) dx 13 x ln x 3 1 01 3 r (0) x3 3 t C C C 0 r cos t r ln x 1) dt 1 2 dr (cos t sin t 2 t t2 2 2) dt C 2t 1 We first show the graph of y r r C sin t 1 t2 2 Graphical support: 2 . 3 x t 2t r (0) 2 3 x ln x 1 C 0 2 3 x3 3 cos t C We first show the graph of y x 1 ( sin t x Graphical support: Let f (x) 1 1 x2 y C f (x) 0, along with the slope field for y x2 x f (x) 1 1, 2x with the slope field for y sin t r 1 along cos t. 1 . x2 [ 6, 4] by [ 3, 3] [ 0.5, 4.21] by [ 9, 21] Next, we show the graph of y We now show the graph of y for y f (x) x 2 x f (x) along with the slope field 1 with the slope field for y r cos t r sin t t 2 along 1. 1. [ 6, 4] by [ 3, 3] [ 0.5, 4.21] by [ 9, 21] Finally we show the graph of y r along with the slope field for y r [ 6, 4] by [ 8, 2] sin t cos t t2 2 2t t 2. 1 284 27. Chapter 6 Review dy y2 dx dy dx y2 dy dx y2 ln y 2 2 y Since 1 C C x x2 2 C g (x)] dx x C. 2 f (x) dx 2(1 2 g (x) dx x) (x x C 2 4e x C C is an arbitrary constant, we may write the...
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