Business Calc Homework w answers_Part_59

Thus 0 4 2 k y dy 2 5 2k sin kx dx 0 k 4 0 0 2

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Unformatted text preview: 95 2 0 2x dx /4 3. sec2 x dx tan x /4 1 ( 1) 2 /4 2 32 x 30 x2 2 0 /4 2 4. x 3) dx (4x 0 3 4 3 5. 9 3 radius 3.) x 2 dx 2x 2 14 x 4 2 (8 4) 0 4 0 9 (This is half the area of a circle of 2 294 Section 7.2 6. Solve x 2 4x x 6. x 2 5x 6 0 (x 6)(x 1) 0 x 6 or x 1 y 6 6 12 or y 1 (6, 12) and ( 1, 5) 7. Solve e x 1 3. 1 6 [(12y 2 (x 1)] 0. Test: e0 e 0 x ( 12y 3 (x 10 3 1) is at a minimum. x2 2y)] dy 2y) dy 1 y2 0 4 3 1 1, i.e., when 5. Use the region’s symmetry: 1. So the solution is (0, 1). 2 2x 10y 2 10 3 y 3 3y 4 3 8. Inspection of the graphs shows two intersection points: (0, 0), and ( , 0). Check: 02 0 sin 0 0 and 2 2 sin 0. 9. Solve (2y 2 2 [2x 2 (x 4 2 2x 2)] dx 2 ( x4 0 2 15 x 5 43 x 3 2 32 5 2 2 x4 x4 x 1 2 (x 2 x2 x2 2 0 0 25 x 5 2 x3 1 2 0 1 3 2 5 2 or 1 1 Throw out the negative solution. 0 (2 y 4 3/2 y 3 y) dy 12 y 2 1 0 1 x3 y 4 3 1 (0, 0), ( 1, 1 2 5 6 0 8. Integrate with respect to y: 1) and (1, 1) 1 10. Use the intersect function on a graphing calculator: 0 [(2 y) y] dy 12 y 2 2y 2 3/2 y 3 1 1 2 2 0 2 3 0 9. Inte...
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This document was uploaded on 10/31/2011 for the course MAC 2311 at University of Florida.

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