Intro to Stat_Part_11

Intro to Stat_Part_11 - 47 iii. 161.34 iv. 0.84 std. dev....

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47 iii. 161.34 iv. 0.84 std. dev. below the mean j. Young k. The mean is most appropriate. From the boxplot the data appear to be relatively symmetric. When the data are symmetric, it is appropriate to use the mean because it incorporates more information from the data. (If the data were skewed, then it would be more appropriate to use the median; but these data are not skewed.) l. IQR = 272.5 – 202.5 = 67; Q1 – 1.5*IQR = 205.5 – 1.5(67) = 105; Q3 + 1.5*IQR = 272.5 + 1.5(67) = 373. All weights are between 105 and 373. There are no outliers. m. Mean – 2(standard deviation) = 240.08 – 2(44.38) = 151.32 ; Mean + 2(standard deviation) = 240.08 + 2(44.38) = 328.84 ; All players’ weights are between 2 standard deviations above and below the mean. Solution to Exercise 2.9 (p. 33) Kamala Solution to Exercise 2.15 (p. 38) a. True b. True c. True d. False Solution to Exercise 2.17 (p. 39) b. 4,3,5 c. 4 d. 3 e. f. 3,5 g. 3.94 h. 1.28 i. 3 j. mode Solution to Exercise 2.19 (p. 40) c. Maybe Solution to Exercise 2.21 (p. 41) a. more children b. 62.4% Solution to Exercise 2.23 (p. 42) b. 51,99 Solution to Exercise 2.24 (p. 42) A Solution to Exercise 2.25 (p. 43) A
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This document was uploaded on 10/31/2011 for the course STA 2023 at University of Florida.

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Intro to Stat_Part_11 - 47 iii. 161.34 iv. 0.84 std. dev....

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