Intro to Stat_Part_40

# Intro to Stat_Part_40 - d t 13 e i CI(3.58 8.42 iii EB =...

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134 CHAPTER 8. CONFIDENCE INTERVALS D. 1 Exercise 8.48: REVIEW QUESTION 17 (Solution on p. 137.) If H and D are mutually exclusive events, P ( H ) = 0.25 , P ( D ) = 0.15 , then P ( H | D ) A. 1 B. 0 C. 0.40 D. 0.0375

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135 Solutions to Exercises in Chapter 8 Solution to Exercise 8.1 (p. 121) a. i. 71 ii. 3 iii. 2.8 iv. 48 v. 47 c. N ± 71, 3 48 ² d. i. CI: (70.15,71.85) iii. EB = 0.85 Solution to Exercise 8.3 (p. 122) a. i. 8629 ii. 6944 iii. 35 iv. 34 c. t 34 d. i. CI: (6243, 11,014) iii. EB = 2385 e. It will become smaller Solution to Exercise 8.5 (p. 123) a. i. 8 ii. 4 iii. 81 iv. 80 c. t 80 d. i. CI: (7.12, 8.88) iii. EB = 0.88 Solution to Exercise 8.7 (p. 124) a. i. 2 ii. 0.1 iii . 0.12 iv. 16 v. 15 b. the weight of 1 small bag of candies c. the average weight of 16 small bags of candies d. N ± 2, 0.1 16 ² e. i. CI: (1.96, 2.04) iii. EB = 0.04 f. i. CI: (1.94, 2.06) iii. EB = 0.06 Solution to Exercise 8.9 (p. 125) a. i. 6 ii. 3 iii. 14
136 CHAPTER 8. CONFIDENCE INTERVALS iv. 13 b. the time for a child to remove his training wheels c. the average time for 14 children to remove their training wheels.
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Unformatted text preview: d. t 13 e. i. CI: (3.58, 8.42) iii. EB = 2.42 Solution to Exercise 8.11 (p. 125) a. i. 320 ii . 400 iii. 0.80 c. N ± 0.80, q ( 0.80 )( 0.20 ) 400 ² d. i. CI: (0.76, 0.84) iii. EB = 0.04 Solution to Exercise 8.13 (p. 126) b. N ± 0.61, q ( 0.61 )( 0.39 ) 1200 ² c. i. CI: (0.59, 0.63) iii. EB = 0.02 Solution to Exercise 8.15 (p. 127) b. N ± 0.86, q ( 0.86 )( 0.14 ) 323 ² c. i. CI: (0.8229, 0.8984) iii. EB = 0.038 Solution to Exercise 8.17 (p. 127) a. i. 7.9 ii. 2.5 iii. 2.8 iv. 20 v. 19 c. N ³ 7.9, 2.5 √ 20 ´ d. i. CI: (6.98, 8.82) iii. EB: 0.92 Solution to Exercise 8.19 (p. 128) a. t 83 b. average cost of 84 used cars c. i. CI: (5740.10, 7109.90) iii. EB = 684.90 Solution to Exercise 8.21 (p. 128) b. N ± 0.63, q ( 0.63 )( 0.37 ) 1000 ² c. i. CI: (0.60, 0.66) iii. EB = 0.03...
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Intro to Stat_Part_40 - d t 13 e i CI(3.58 8.42 iii EB =...

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