Chemistry Solved_Part_45

Chemistry Solved_Part_45 - ©2010 Digital Interactive Video...

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Unformatted text preview: ©2010 Digital Interactive Video Education Week 26 134 4) Ag 2 CrO 4 + Al → 2Ag + Al 3+ + CrO 4 2- (assume the oxidation number of Cr does not change). 5) What is the number of equivalents per mole of: MnO 4- in problem 2, Fe in problem 3, and Al in problem 4? 3 pts. 6) If 0.028 L of a 0.068 M solution of potassium dichromate (K 2 Cr 2 O 7 ) titrates 0.043 L of a nitric oxide (NO 2 ) solution, what is the concentration of the nitric oxide solution? The balanced ionic equation is shown below. 3 pts. Cr 2 O 7 2- + 6NO 2 + 2H + → 2Cr 3+ + 6NO 3- + H 2 O 2(+1) +6 2(-4) 0 0 +3 +6 2(-9) ox. ( Al → Al 3+ + 3e- )2 red. ( Ag 2 CrO 4 + 2e- → 2Ag + CrO 4 2- )3 2Al + 3Ag 2 CrO 4 → 2Al 3+ + 6Ag + 3CrO 4 2- 5 eq mole MnO 4 2 eq mole Fe 3 eq mole Al , , 2(+6) 7(-2) +4 (-2)2 +3 +5 2(-3) N 1 V 1 = N 2 V 2 ox. NO 2 → NO 3- + e- red. Cr 2 O 7 + 6e- → 2Cr 3+ ( ) = .408N .408N(.028L) = N 2 (.043) N 2 = .2657 = .27 M NO 2 .068 mol L 6 e 1 mole ©2010 Digital Interactive Video Education Week 26...
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Chemistry Solved_Part_45 - ©2010 Digital Interactive Video...

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