ees3040HW9solns_fa10

# ees3040HW9solns_fa10 - Fall 2010 1 EES 3040 Homework 9...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Fall 2010 1 EES 3040 Homework 9 Solutions Reading Assignment: D&M1 Ch 1 (pp. 18-21); Ch 11 (pp. 436-458, 471-484) or D&M2 Ch 12, pp. 524-547, 571-582; and internet Problem 1. (3 pts.) Convert the following indoor air quality standard from ppm to mg/m 3 (at 25 o C and 1 atm), or vice versa. Hint: see Chapter 2 and HW1. a.) Naphthalene (C 10 H 8 ), 10 ppm MW = 10(12)+8(1) = 128 Conversion equation: mg/m 3 = (ppm)(MW)/24.465 for 25 o C and 1 atm mg/m 3 = (10 ppm)(128) / 24.465 = 52.3 mg/m 3 (2 pts.) b.) Nicotine (C 10 H 14 N 2 ), 1.0 mg/m 3 MW = 10(12)+14(1)+2(14)=162 ppm = (1.0 mg/m 3 )(24.465) / 162 = 0.15 ppm (2 pts.) Problem 2. ( 4 pts.) Indoor air quality Given: I = 0. 35 /hr, Area A = 2 50 m 2 , Volume V = 7 2 5 m 3 , Radon emission rate =0. 6 pCi/m 2-s. Decay rate constant k = 7.6 x 10-3 /hr. Steady-state concentration, C ∞ = ? Assume Ambient (outdoor) conc Ca = 0 Emission rate E = (0. 6 pCi/m 2-s)(2 5 0 m 2 ) = 1 5 0 pCi/s (0.5 pts.) Q = IV = (0. 35 /hr)(7 2 5 m 3 ) = 25 3.7 5 m 3 /hr (0.5 pts.) C ∞ = (QC a + E) / (Q + kV) (Eqn 11-23 in text) = [0 + 1 5 0 pCi/s)(3600s/hr)] / [ 25 3.7 5 m 3 /hr + (7.6 x 10-3 /hr)(7 2 5 m 3 )] = 2083 pCi/m 3 (3 pts.) Problem 3. (3 pts.) Same as Problem 2, but now a 2-story house with A = 12 5 m 2 per floor New emission rate E = (0. 6 pCi/m 2-s)(12 5 m 2 ) = 75 pCi/s since radon enters house through the ground C ∞ = (QCa + E) / (Q + kV)...
View Full Document

## This note was uploaded on 10/29/2011 for the course EES 3040 taught by Professor Chan-hilton during the Fall '10 term at FSU.

### Page1 / 3

ees3040HW9solns_fa10 - Fall 2010 1 EES 3040 Homework 9...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online