Physics 401 Final ExamTodd Morstein

Physics 401 Final ExamTodd Morstein - Physics 401 Final...

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Physics 401 Final Exam Todd Morstein 1.A. Student #1 reported: a full moon in the south east at 9:00 pm I know student #1 is suppose to be wrong most times but this time he is correct. The full moon is straight south and at it’s peak in the sky at 12:00 am. It rises at 6:00 pm and it rises in the east therefore the moon rises in the east by 9:00 pm the moon will be in the south eastern sky. Student #2 reported : a waning gibbous in south west at 9:00 pm A waning gibbous would be at it’s peak at 3 am. The waning gibbous will be in the south west at 6:00 am and not at 9:00 pm. The waning gibbous rises at 9:00 pm and would be in the south east. Student #3 reported: a first quarter moon in the south west at 9:00 pm. The first quarter moon will be at it’s peak at 6:00 pm and will be in the southwest at 9:00 pm. Student #4 reported: a waning crescent just rising in the east at 9:00 pm. A waning crescent will be at it’s peak an 9:00 am. The waning crescent will rise at 3:00 am and will set by 3:00 pm therefore the moon will not be rising at 9:00 pm. 1.B. Three nights later student #3 will be seeing a waxing gibbous. It will be rising at 9:00 pm and will be in the east. 1. C. The moon will be rising just after 12:00 am. The moon is in the 3 rd quarter (waning quarter). When the moon is on the eastern horizon facing east the sun is following the moon. It would lead the sun by 6 hours. 12:00 am 6:00 am 12:00 pm 6:00 pm
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2. V1 5 V2 5 A B C D E F G H A. The sum of the voltage across any path that is parallel across the battery has equivalent voltage across the path. The sum of all voltages in series equal and across the battery is equal to the voltage across the battery. In path F, G, H if all bulbs are identical the voltage across each bulb is 1/3 of the voltage through the battery. The path with A, B, C, D, and E have has less resistance then F, G, and H. The additional path created by B and C in parallel with D decrease the resistance in the circuit. The parallel branch BC and D has less resistance then G. R BC||D < R G if G=1/3V batt BC||D <1/3 V batt V A + V BC||D + V E = V batt The voltage in all paths have to V F + V G + V H = V batt Equal the voltage across the Battery. V F = V G = V H = 1/3 V batt Equivalent resistances in series V A = V E dived the voltage equally. V
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This document was uploaded on 10/29/2011 for the course PHSX 201 at MSU Bozeman.

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Physics 401 Final ExamTodd Morstein - Physics 401 Final...

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