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# Hw 1 key - 12 0.77 54112.554 Ed=Fd/Fde 0.8738977 Max pull...

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1.a 1.3.a Engine Fuel Angular Power Calculate the static tension in the fast line Speed Torque ConsumptioVelocity Output W 200000 rpm ft-lbs gal/hr ϖ HP P 800 1200 1400 25.3 7539.816 319.87098 n 10 1000 1550 19.7 6283.18 295.11906 E 0.81 800 1650 15.7 5026.544 251.3272 600 1700 12.1 3769.908 194.20738 24691.358 w/(en) 1.b 1.3.b Fuel Heat Overall Calculate the maximum hook hp available consump consumed efficiency 648 hp P*E lbm/min hp % 3.036 1361.692 23.49% 1.3.c Calculate the maximum hoisting speed 2.364 1060.2898 27.83% vb=P/W 1.884 845.00255 29.74% 106.92 ft/min 1.452 651.244 29.82% t=90/vb 0.8417508 min 1.c 188.4 1.3.d Calculate the derrick load Fd=(1+E+En)W/En 1.2 244691.36 lbf Compute tension in the fast line Hook load 500000 1.3.e No. Efficiency fast line Calculate the Maximujm equivalent derrick load linew factor tension Fde=((n+4)/n)*W n fraction lbf 280000 lbf 6 0.874 95347.063 8 0.841 74316.29 1.3.f 10 0.81 61728.395 Calculate the derrick efficiendy factor
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Unformatted text preview: 12 0.77 54112.554 Ed=Fd/Fde 0.8738977 Max pull 1.6 Ratings w/ SF S.F. 2 Ldemax 500000 250000 Tmax 51200 25600 Tdpmax 396000 198000 n 8 E 0.841 How hard can the driller pull on stuck drill pipe Wmax assuming the derrick is the limiting factor is 166666.67 lbf If the drilling line is the limiting factor, the tension in the fast line would be used to calculate the maximum hook load Tfast W/En Wmax TfastEn Wmax 344473.6 lbf If the drill pipe is the limiting factor, the max hook load will be 1/2 of the tension rating of the DP Wmax 198000 The actual limiting factor is the lower of the three In this case the derrick is the limiting factor Wmax 166,667 lbf + × = + = 4 F W W for 4 de n n Solve W n n F Since de...
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