Unformatted text preview: Ω and 80 Ω resistors by using the current divider equation. a) ° 1 = 4 ± ∗ 120 120 + 80 ² = 2.4 ± ° 2 = 4 ± ∗ 80 120 + 80 ² = 1.6 ± b) To find the voltage across these parallel resistors, we will combine the above resistors into an equivalent resistor, and use Ohm’s law to determine the voltage drop. Remember, parallel resistors have the same voltage drop; this is why we can make this transformation. 1 120 + 1 80 ² − 1 = 48 Ω Using Ohm’s law: V = IR, where I = 4A, R = 48 Ω V = 192V...
View
Full Document
 Spring '05
 Unknown
 Electrical Engineering, Volt, Resistor, ohm, Electrical resistance, Sample Problem Topic

Click to edit the document details