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Unformatted text preview: Since the ideal source is a current sou rce, and it is going against the direction from v 1 to ground, we defined it as a negative value. Solving the linear equation, we find v 1 . Note: V 1 = V c) V 1 = 192V d) Knowing the voltage at the node, and knowing that parallel resistors share the same voltage drop, we can simply use Ohms law to determine the currents through each branch. V = I *R 192V = I * 80 192V = I * (30 +90 ) b) I 2 = 1.6A a) I 1 = 2.4A...
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This note was uploaded on 10/30/2011 for the course EE 215 taught by Professor Unknown during the Spring '05 term at University of Washington.
 Spring '05
 Unknown
 Electrical Engineering, Volt

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