Unformatted text preview: Since the ideal source is a current sou rce, and it is going “against” the direction from v 1 to ground, we defined it as a negative value. Solving the linear equation, we find v 1 . Note: V 1 = V c) V 1 = 192V d) Knowing the voltage at the node, and knowing that parallel resistors share the same voltage drop, we can simply use Ohm’s law to determine the currents through each branch. V = I *R 192V = I * 80 Ω 192V = I * (30 Ω +90 Ω ) b) I 2 = 1.6A a) I 1 = 2.4A...
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 Spring '05
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 Electrical Engineering, Volt, Resistor, ohm, Electrical resistance

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