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Unformatted text preview: Ohm s law, if we inspect this more closely, we are defining currents. V = IR, rearranging this equation, we get: V/R = I Thus, if there were a current source in the circuit, we would simply add the value to the equation. c) If we solve the function above, we find that v1 = 40V. Knowing the voltage at the node, and knowing that parallel resistors share the same voltage drop, we can simply use Ohm s law to determine the currents through each branch. V = I *R 40 = I * 80 40 = I * 20 b) I 80 = .5A a) I 20 = 2A...
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This note was uploaded on 10/30/2011 for the course EE 215 taught by Professor Unknown during the Spring '05 term at University of Washington.
 Spring '05
 Unknown
 Electrical Engineering, Volt

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