Unformatted text preview: perturbation. Use second order perturbation theory. HINT : There is one hard integral. This can be done trivially, if you know the following ClebschGordon coeﬃcient: ° ° m , 1 0  ° − 1 m , ° 1 ² = − ° ° 2 − m 2 ° (2 ° + 1) ± 1 / 2 . 3. Two nonidentical particles, each of mass m , are con±ned in one dimension to an impenetrable box of length L . What are the wave functions and energies of the three lowestenergy states (i.e. in which at most one particle is excited out of its ground state)? If an interaction potential of the form V 12 = λδ ( x 1 − x 2 ) is added, calculate to ±rst order in λ the energies of these three lowest states, along with their wave functions to zeroth order in λ . 2...
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This document was uploaded on 10/31/2011.
 Spring '09
 Energy, Gravity, Mass

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