{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Yl10_lah

Yl10_lah - 1 Vesinikasiidi(HN3 aururhk 22,75 C juures on 58...

This preview shows pages 1–2. Sign up to view the full content.

1. Vesinikasiidi (HN 3 ) aururõhk –22,75 °C juures on 58 torri ja 25,0 °C juures 512 torri. Arvutage vesinikasiidi standardne aurustumisentalpia, standardne aurustumisentroopia, standardne aurustumise vabaenergia, keemistemperatuur normaaltingimustel. Lahendus: ln p 2 p 1 = H v R ⋅ 1 T 1 1 T 2 ⇒ H v = R ln p 2 p 1 1 T 1 1 T 2 = 8.314 J K mol ln 512 T 58 T 1 250.4 1 298.15 = 28310 J mol ln p p 0 = − H v o RT S v o R ⇒ S v o = Rln p p 0 H v o T S v o = 8.314 J K mol ln 512 Torr 760 Torr 28310 J mol 289.15 K = . 91 7 J mol K G v o = H v o T ⋅ S v o = 28310 J mol 298.15 K 91.7 J K mol = 983 J mol Keemistemperatuurile vastab, et p = p 0 ln p p 0 = 0 ja saame − H v o RT S v o R = 0 H v o RT = S v o R T b = H v o S v o = 28310 J mol 91.7 J K mol = 308.7 K = . 35 7 o C Vastus : 28.31 kJ/mol; 91.7 J/(K*mol); 983 J/mol; 308.7 K 2. Heeliumi faasidiagramm on toodud kõrval. Milline on vedela He-II eksisteerimise maksimaalne temperatuur? Milline on heeliumi normaalne keemistemperatuur? Kas tahke heelium saab sublimeeruda? 3. Süsiniku faasidiagramm on toodud kõrval. Millist rõhku on vaja rakendada, et 2000 K juures muuta grafiit teemandiks? Milline on minimaalne temperatuur vedela süsiniku eksisteerimiseks rõhul 10 000 atm?

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern