Yl11_lah - 1. Gaaside segu koosneb CO(g)-st, H2(g)-st ja...

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1. Gaaside segu koosneb CO (g) -st, H 2(g) -st ja CH 4(g) -st. Arvutage molaarse vabaenergia muutus 25°C juures (eeldades, et reaktsioone ei toimu): a) CO partsiaalrõhku tõstetakse 0.500 baarilt 25.00 baarini; b) H 2 partsiaalrõhku alandatakse 10.00 baarilt 5.00 baarini. Lahendus : G m g, p = G m o g  RTln p p 0 ⇒ G m = RT ln p 2 p 1 a) G m = 8.314 J K mol 298 K ln 25.00 . 0 500 = . 9 69 kJ b) G m = . 8 314 J K mol 298 K ln 5.00 10.00 =− 1.72 kJ Vastus: 9.69 kJ/mol; -1.72 kJ/mol 2. Arvutage molaarse vabaenergia muutus 25°C juures kui a) 0.450 M FeCl 3(aq) lahjendatakse 0.350 M-ni; b) vee kontsentratsioon etanoolis tõuseb 0.175M-lt 0.350 M-ni. Lahendus : G m l ,c = G m o l  RTln [ J ] [ J ] 0 ⇒ G m = RT ln [ J ] 2 [ J ] 1 a) G m = . 8 314 J K mol 298 K ln . 0 350 0.450 =− 0.62 kJ b) G m = 8.314 J K mol 298 K ln 0.350 0.175 = 1.72 kJ Vastus: -0.62 kJ/mol; 1.72 kJ/mol 3. Arvutage reaktsiooni CaCO 3(t)= CaO (t) +CO 2(g) tasakaalukonstant 25°C juures! CaCO
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This note was uploaded on 11/01/2011 for the course LOTE 101 taught by Professor Anso during the Fall '09 term at Uni. Tartu.

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Yl11_lah - 1. Gaaside segu koosneb CO(g)-st, H2(g)-st ja...

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