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ACReview

# ACReview - ECE225 REVIEW PROBLEMS Problem 1(Nodal Analysis...

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ECE225 REVIEW PROBLEMS SPRING 2010 Problem 1 (Nodal Analysis) Problem 2 (Mesh Analysis) Problem 3 (Superposition) Problem 4 (Superposition) Problem 5 (Thevenin Equivalent Circuit) 1

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Problem 1 (Nodal Analysis) 4 0 V o - + o ^ V j4 -j5 - + 2 0 = ˜ V o - 4 6 0 o 2 + ˜ V o - j 5 + ˜ V o j 4 4 6 0 o 2 = 1 2 + 1 - j 5 + 1 j 4 ˜ V o 2 = (0 . 5 - j 0 . 05) ˜ V o ˜ V o = 2 0 . 5 - j 0 . 05 = 40 10 - j 1 = 40 101 6 - 5 . 71 o = 3 . 98 6 5 . 71 o V 2
Problem 2 (Mesh Analysis) o 6sin 2t 4 - + - + 2 H 4 0.25 F o i - j4 o 10 0 V ^ ^ ^ 6 -90 V V o I 2 I 1 I -j2 + 10cos 2t V - + ( 10 = 4 ˆ I 1 - j 2( ˆ I 1 + ˆ I 2 ) - j 6 = j 4 ˆ I 2 - j 2( ˆ I 1 + ˆ I 2 ) ( (4 - j 2) ˆ I 1 - j 2 ˆ I 2 = 10 - ˆ I 1 + ˆ I 2 = - 3 ˆ I 1 = fl fl fl fl fl 10 - j 2 - 3 1 fl fl fl fl fl fl fl fl fl fl (4 - j 2) - j 2 - 1 1 fl fl fl fl fl = 10 - j 6 4 - j 4 ˆ I 2 = fl fl fl fl fl (4 - j 2) 10 - 1 - 3 fl fl fl fl fl fl fl fl fl fl (4 - j 2) - j 2 - 1 1 fl fl fl fl fl = - 2 + j 6 4 - j 4 ˆ I o = ˆ I 1 + ˆ I 2 = 10 - j 6 4 - j 4 + - 2 + j 6 4 - j 4 = 8 4 - j 4 = 2 1 - j 1 = 2 6 0 o 2 6 - 45 o = 2 6 45 o = 1 . 414 6 45 o i o ( t ) = 2 cos(2 t + 45 o ) = 1 . 414 cos(2 t + 45 o ) A 3

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Problem 3 (Superposition) DC CIRCUIT - + 4 i (t) o 1 H
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