Week_3_Assignment_Guidance (2)

Week_3_Assignment_Guidance (2) - Indian Method and...

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Click to edit Master subtitle style 6/7/11 Indian Method and Quadratic Formula Math 126 Assignment 3
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6/7/11 Indian Method (Solving problem c: Step a) X2 + 12X – 64 Step a) Move constant term to right. The constant term is the term with no X variable beside it. The constant term is 64 X2 + 12X = 64
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6/7/11 Indian Method (Solving problem c: Step b) Step b) Multiply each term in the equation by four times the coefficient of the X2 term. The X2 coefficient in this case is 1. If there is no number in front of the X2 term, then the number is 1. 1 X2 + 12X – 64. So four times 1 equals 4 ( 4 )X2 + (12 *4 )X = 64 *4 = 4X2 + 48X
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6/7/11 Indian Method (Solving problem c: Step c) Square the coefficient of the original x term and add it to both sides of the equation. Here is the original equation X2 + 12X – 64 The X term is 12, so 122 = 144. So add 144 to both sides. Start from where you left off at step b.
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6/7/11 Indian Method (Solving problem c: Step d) Take square of both sides
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Week_3_Assignment_Guidance (2) - Indian Method and...

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