HW #3-solution - PGE 337 HW #3 SOLUTION KEY Question 1 a I....

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
PGE 337 HW #3 SOLUTION KEY Question 1 a I. II. The median is the 50 th percentile and can be obtained from a plot of the cdf -1 2 We see that the median is in the discontinuity observed in the cdf. Since only two outcomes are possible and there is a jump at -1 directly to 2/3, the median is -1. III. The mode is -1 since it has the highest pdf value IV. Since the mean is different from and less than the mode, then this distribution is asymmetric and skewed to the left. This is also confirmed by the difference between the median and the mean values. Question 1 b Given the RV I. II. Median is 50 th percentile given as the cdf value at X = 0.5 Solving the quadratic gives since III. Mode is the maximum of the pdf i.e. IV. The mean, median and mode are similar hence the distribution can be considered fairly symmetric Question 2 a Given the RV I. Solving the quadratic gives since II. Similarly as above, III. Interquantile range is Question 2 b Given the RV
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Simplifying gives Question 2 c Given the RV
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 4

HW #3-solution - PGE 337 HW #3 SOLUTION KEY Question 1 a I....

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online