Horvath Practice Problems 49

Horvath Practice Problems 49 - 2 . 3 × 10 − 3 M solution...

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The pH Scale The inverse relationship between £ H 3 O + ¤ and £ OH ¤ is seen in the pH scale. Consider taking the negative log of K w , log K w = log ¡ 1 . 0 × 10 14 ¢ = log ¡£ H 3 O + ¤£ OH ¤¢ 14 = log £ H 3 O + ¤ | {z } pH log £ OH ¤ | {z } pOH 14 = pH + pOH The pH of Strong Acids and Bases If one is dealing with strong acids and bases, determination of pH is relatively easy based on the LeChatelier arguments above. Example 1 : What is the pH of a 2 . 3 × 10 3 Mso lutionofHC
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Unformatted text preview: 2 . 3 × 10 − 3 M solution of H 3 O + . The pH is simply pH = − log ¡ 2 . 3 × 10 − 3 ¢ = 2 . 63 Example 2 : What is the pH of a 2 . 3 × 10 − 3 M solution of NaOH. Since NaOH is a strong base, it fully dissociates to produce a 2 . 3 × 10 − 3 M solution of H 3 O + . The pOH is pOH = − log ¡ 2 . 3 × 10 − 3 ¢ = 2 . 63 From the 14 = pH + pOH relationship pH = 14 − 2 . 63 = 11 . 36 48 WATER AND PH...
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This document was uploaded on 11/01/2011 for the course CHM 2046 at University of Florida.

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