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Horvath Practice Problems 76

# Horvath Practice Problems 76 - titration example 2...

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Rearranging and using the quadratic formula gives x =[ OH ]= 6 . 0 × 10 6 . The pH is then pH =14 ¡ log £ 6 . 0 × 10 6 ¤¢ =8 . 78 Notice that the pH at the equivalence point is not 7.0 as it is in the case of a strong acid strong base titration. After the endpoint the niacin is the limiting reagent. So the problem becomes exactly like the strong acid strong base case. We f gure out how much OH is left over and get the pH from that. Group Work 1. Calculate several values for the strong acid strong base
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Unformatted text preview: titration example 2. Calculate several values for the weak acid strong base titration example 3. What is the pH at the equivalence point for the titration of 25 mL of 0.10M NH 3 with HCl. Homework Reading : Kotz and Treichel, 18.3 Problems : Chapter 18: 23, 24, 25, 29, 79, 83 *Note* these are not due until after the next lecture. TITRATIONS PART I 75...
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