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Horvath Practice Problems 119

# Horvath Practice Problems 119 - As we expected from earlier...

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As we expected from earlier. Example : What is ε for a Daniel cell at 300 K when the concentration of Cu 2+ is 0.100 M and the concentration of Zn 2+ is 0.001 M? Zn(s) + Cu 2+ (aq) Cu(s) + Zn 2+ (30.6) First we need ε ° which we found last lecture to be 1.10 V. Then we use the Nernst equation, ε = 1 . 10 8 . 314 × 300 2 × 96485 ln 0 . 100 0 . 001 = 1 . 04 V The n = 2 because 2 electrons are transferred from the zinc to the copper during the reaction. Notice that even though the concentrations di ff er by a factor of 100, the di ff erence in voltage from the standard potential is minimal. Group Work 1. Explicitly derive the Nernst equation from the 4 G equa- tion. 2. What is K for the Daniels cell reaction?
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