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Horvath Practice Problems 120

Horvath Practice Problems 120 - The Nernst equation becomes...

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The Nernst equation becomes ε = 0 RT n 1 F ln [ Na] 1 [ Na] 2 = RT F ln [ Na] 1 [ Na] 2 (30.8) So we see that if [ Na] 1 6 = [ Na] 2 then a potential will de- velop. (a) What is the potential of a sodium concentration cell if the di ff erence in concentration it a factor of 10? how about 100? how about 1000?
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