# Example1 - Charge conservation q 10 = q 1 q 23 48 = C 1 V 1 C 23 V 1(V 1 = V 23 Find V 1 V 1 = 48(C 1 C 23 = 8 V Find q 1 q 1 = C 1 V 1 = 32 μ C q

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Example: Find q and V on All  Capacitors C is charged in position A, then S is  thrown to B position Initial voltage across C 1 : V = 12 Initial charge on C 1 : q 10  = 12 x 4 = 48 μ C After switch is thrown to B: Charge flows from C to C and C 3 V = V 23  (parallel branches) q and q in series: q = q = q (C = 2 μ F)
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Unformatted text preview: Charge conservation: q 10 = q 1 + q 23 48 = C 1 V 1 + C 23 V 1 (V 1 = V 23 ) Find V 1 : V 1 = 48 / (C 1 + C 23 ) = 8 V Find q 1 : q 1 = C 1 V 1 = 32 μ C q 23 = 48 – 32 = q 2 = q 3 = 16 μ C V 2 = q 2 / C 2 = 2.67 V V 3 = q 3 / C 3 = 5.33 V...
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## This document was uploaded on 11/01/2011 for the course PHY PHY2049 at Broward College.

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