3580_Spring2011_Midterm _3_KEY - Name_KEY_ Chemistry 3580...

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Name______KEY______________________ Chemistry 3580 Instructor: William Dichtel Thursday, April 21, 2011 Third Midterm Examination (1) ____________ (18 Points) (2) ____________ (16 Points) (3) ____________ (40 Points) (4) ____________ (18 Points) (5) ____________ (24 Points) (6) ____________ (42 Points) (7) ____________ (42 Points) TOTAL ____________ (200 POINTS) Notes: There should be 11 pages in this exam (including this one). Please ensure that your copy of the exam is not missing pages. There are no calculators allowed. Please write your initials at the top of each page. Please write all answers in the spaces provided. Only these will be graded.
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Page 2 / 11 1. (18 points) Samples of enantiopure compounds 1 , 2 , and 3 are treated with mild aqueous base (NaOH / H 2 O). Compound 1 rapidly loses the ability to rotate polarized light but its 1 H NMR spectrum does not change. Compound 2 becomes a mixture of two compounds that are separable and have different 1 H NMR spectra. Compound 3 remains unchanged. Briefly explain each of these observations. NOTE: No carbonyl condensation or addition reactions
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This note was uploaded on 11/01/2011 for the course CHEM 3580 taught by Professor Sogah, d during the Spring '08 term at Cornell University (Engineering School).

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3580_Spring2011_Midterm _3_KEY - Name_KEY_ Chemistry 3580...

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