{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

PHY 101 notes - PHY 101 9/1 Speed average instantaneous...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
PHY 101 9/1 Speed –average - instantaneous velocity vector acceleration –average - due to gravity v=s=d/t a=change in V/t average speed –s -s = d/t total distance traveled over time elapsed distance =1/2 acceleration * time (squared) falling distance d= initial distance + initial velocity*time+1/2 acceleration * time squared acceleration of gravity: 9.8 m/sec2 initial velocity: v o or v I instantaneous speed: speed at any moment in time velocity: speed with direction, a “Vector” quantity vector has magnitude –size, how large AND direction acceleration: change in v with time average acceleration a= change in v over change in t 09/03/09 d=v/t d=1/2(a)(t2) v= d/t v=change d/change t
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
9/22 EXAM ALL MECHANICAL OR THERMAL ENERGY Exam equations on one side Need calc, pencil Energy can be neither created nor destroyed, but only transformed from one form to another Temp – Average KE of the atoms and molecules comprising the object Thermometer – Celsius, Kelvin, and Farenheidt Kelvin’s zero is impossible, 0 C = 273 K
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern