CH2DEF~1 - CHAPTER 16 EQUILIBRIA Problems to prepare...

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CHAPTER 16 EQUILIBRIA Problems to prepare students for Chem 162 hourly exam. SOLUBILITY PRODUCT COMPLEX ION EQUILIBRIA E. Tavss 3/11 Chapter 15B practice problems 1
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SOLUBILITY PRODUCT CHEM 162-2007 EXAM II + ANSWERS CHAPTER 16A – EQUILIBRIA SOLUBILITY PRODUCT 1. Which of the following compounds are more soluble in acid than in pure water? X. CaCO 3 Y. Fe(OH) 3 Z. AgCl (a) X only (b) X and Y only (c) Y only (d) X, Y, and Z (e) Y and Z only X. CaCO 3 Ca 2+ + CO 3 2- CO 3 2- + H 3 O + HCO 3 - + H 2 O The acid removes carbonate ions; hence, the reaction shifts to the right, making the CaCO 3 more soluble. Y. Fe(OH) 3 Fe 3+ + 3OH - OH - + H 3 O + 2H 2 O The acid removes hydroxide ions; hence, the reaction shifts to the right, making the Fe(OH) 3 more soluble. Z. AgCl Ag+ + Cl - Cl - + H 3 O + No Reaction Chloride ion is the conjugate base of a strong acid, HCl. Hence, the chloride ion is such a weak base, that it doesn’t act as a base in an aqueous solution. Therefore, addition of acid has no effect on chloride ion, so there is no effect on the solubility of AgCl. CHEM 162-2007 EXAM II + ANSWERS CHAPTER 16A – EQUILIBRIA SOLUBILITY PRODUCT 2. If x = molar solubility, K sp = solubility product, which of the following compounds would have the relationship: 27x 4 = K sp ? (a) AgCl (b) Ag 2 CO 3 (c) Ag 3 PO 4 (d) Bi 2 S 3 (e) PbI 2 Chapter 15B practice problems 2
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(a) AgCl Ag + + Cl - AgCl Ag + + Cl - Initial Y 0 0 Change -X +X +X Equilibrium Y-X +X +X [Ag + ][Cl - ] = K sp [X][X] = X 2 = K sp (b) Ag 2 CO 3 2Ag + + CO 3 2- Ag 2 CO 3 2Ag + + CO 3 2- Initial Y 0 0 Change -X +2X +X Equilibrium Y-X +2X +X [Ag + ] 2 [CO 3 2- ] = K sp [2X] 2 [X] = 4X 3 = K sp (c) Ag 3 PO 4 3Ag + + PO 4 3- Ag 3 PO 4 3Ag + + PO 4 3- Initial Y 0 0 Change -X +3X +X Equilibrium Y-X +3X +X [Ag + ] 3 [PO 4 3- ] = K sp [3X] 3 [X] = 27X 4 = K sp (d) Bi 2 S 3 2Bi 3+ + 3S 2- Bi 2 S 3 2Bi 3+ + 3S 2- Initial Y 0 0 Change -X +2X +3X Equilibrium Y-X +2X +3X [Bi 3+ ] 2 [S 2- ] 3 = K sp [2X] 2 [3X] 3 = 108 X 5 = K sp (e) PbI 2 Pb 2+ + 2I - PbI 2 Pb 2+ + 2I - Initial Y 0 0 Change -X +X +2X Equilibrium Y-X +X +2X [Pb 2+ ][I - ] 2 = K sp [X][2X] 2 = 4X 3 = K sp Chapter 15B practice problems 3
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CHEM 162-2007 EXAM II + ANSWERS CHAPTER 16A – EQUILIBRIA SOLUBILITY PRODUCT 4. AgCl K sp = 1.8 x 10 -10 AgBr K sp = 5.0 x 10 -13 When AgNO 3 solution is added to a flask originally containing 0.010 M NaCl and 0.010 M NaBr, the more insoluble AgBr precipitates first. What is the concentration of Br - remaining in the flask when AgCl first precipitates? Assume that adding the AgNO 3 solution makes only a negligible change in total volume. (a)
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CH2DEF~1 - CHAPTER 16 EQUILIBRIA Problems to prepare...

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