Chem 161-2010 Chapter 3B some Tavss practice problems + solutions

Chem 161-2010 Chapter 3B some Tavss practice problems + solutions

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Unformatted text preview: BALANCING CHEMICAL REACTIONS 10 Chapter 3 Stoichiometry: Chemical Calculations Balancing chemical equations In the combustion of hexane, C 6 H 14 , reacts with O 2 to produce carbon dioxide and water. How many moles of O 2 are required to react with 1.0 mole of hexane? A . 9.5 B. 19 C. 9 D. 9 E. 3 C 6 H 14 + O 2 CO 2 + H 2 O Balance the largest molecule first, and the smallest (e.g., the elements) last. C 6 H 14 + O 2 6CO 2 + H 2 O C 6 H 14 + O 2 6CO 2 + 7H 2 O C 6 H 14 + 19/2 O 2 6CO 2 + 7H 2 O 2C 6 H 14 + 19O 2 12CO 2 + 14H 2 O A 24 Chapter 3 - Stoichiometry Balancing chemical equations In the combustion of butane, C 4 H 10 , butane reacts with O 2 to produce carbon dioxide and water. When the equation for this combustion is balanced with the smallest possible integer coefficients, what is the coefficient of O 2 A. 4 B. 5 C. 7 D. 9 E . 13 C 4 H 10 + O 2 CO 2 + H 2 O C 4 H 10 + O 2 4CO 2 + H 2 O C 4 H 10 + O 2 4CO 2 + 5H 2 O C 4 H 10 + 13/2 O 2 4CO 2 + 5H 2 O 2C 4 H 10 + 13O 2 8CO 2 + 10H 2 O 14. Chapter 3 Balancing Chemical Equations Consider the reaction wPCl 5 + xH 2 O yPOCl 3 + zHCl This equation is balanced when A. choose this choice if none of the others is correct B . w = 1, x = 1, y = 1, z = 2 C. w = 2, x = 2, y = 2, z = 1 D. w = 2, x = 2, y = 2, z = 2 E. w =1, x =2, y = 2, z = 4 wPCl 5 + xH 2 O yPOCl 3 + zHCl Begin with the most complex molecule, which is either PCl5 or POCl3. The Ps are already balanced. Balance the Cls. The coefficient to balance the Cls must go on the HCl because if the coefficient goes on the POCl3 then the Ps will no longer be balanced. PCl 5 + H 2 O POCl 3 + 2HCl Everything is now balanced. CHAPTER 3 - STOICHIOMETRY BALANCING CHEMICAL REACTIONS 3-83 Balance the following equations representing combustion reactions: a. C 12 H 22 O 11(s) + O 2(g) CO 2(g) + H 2 O (g) a. C 12 H 22 O 11(s) + 12O 2(g) 12CO 2(g) + 11H 2 O (g) b. C 6 H 6(l) + O 2(g) CO 2(g) + H 2 O (g) b. C 6 H 6(l) + (15/2)O 2(g) 6CO 2(g) + 3H 2 O (g) b. 2C 6 H 6(l) + 15O 2(g) 12CO 2(g) + 6H 2 O (g) c. 2Fe (s) + (3/2)O 2(g) Fe 2 O 3(s) c. 4Fe (s) + 3O 2(g) 2Fe 2 O 3(s) d. C 4 H 10(g) + O 2(g) CO 2(g) + H 2 O (g) d. C 4 H 10(g) + (13/2)O 2(g) 4CO 2(g) + 5H 2 O (g) d. 2C 4 H 10(g) + 13O 2(g) 8CO 2(g) + 10H 2 O (g) e. FeO (s) + O 2(g) Fe 2 O 3(s) e. 2FeO (s) + (1/2)O 2(g) Fe 2 O 3(s) e. 4FeO (s) + O 2(g) 2Fe 2 O 3(s) REACTION STOICHIOMETRY 31 Chapter 3 Stoichiometry: Chemical Calculations Reaction Stoichiometry In a series of reactions, all the carbon in Na 2 CO 3 is converted into Na 3 Fe(CN) 6 . What amount of Na 3 Fe(CN) 6 will be produced, if you start with 0.500mol of Na 2 CO 3 , assuming 100% yield?...
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Chem 161-2010 Chapter 3B some Tavss practice problems + solutions

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