{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Chem 161-2010 Tavss' practice problems H&amp;P chapter 1

# Chem 161-2010 Tavss' practice problems H&amp;P chapter...

This preview shows pages 1–9. Sign up to view the full content.

CHAPTER 1 – CHEMISTRY: MATTER AND MEASUREMENT PRACTICE PROBLEMS DR. ED TAVSS Units/unit conversions/dimensional analysis Classification of matter Significant Figures/Precision/Accuracy Miscellaneous 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
UNITS/UNIT CONVERSIONS/DIMENSIONAL ANALYSIS 12 The density of gold is 19.3 g/cm 3 . What is the density of gold in lb/in 3 ? A . 0.697 B. 19.3 C. 100 D. 1000 E. 1.20 × 10 3 454 g = 1 lb 2.54 cm = 1 in 19.3g/cm 3 → lb/in 3 Convert numerator and denominator separately; then combine them. Numerator: 19.3g → lb 19.3g x (1 lb/454g) = 0.0425 lb Denominator: cm 3 → in 3 cm 3 x (1 in/2.54cm) 3 = 0.0610 in 3 Combining the numerator and denominator: 0.0425 lb/0.0610 in 3 = 0.697 lb/in 3 A 2
23 The value of gold is \$472 per troy ounce. What is the value of the cube of gold 2.00 cm on a side? Given: 1 troy ounce = 31.1 g density of gold: 19.3 3 cm g A . \$2340 B. \$5460 C. \$1520 D. \$3410 E. \$4250 The volume of a cube of gold = (2.00 cm) 3 = 8 cm 3 . Plan: Volume → grams → troy ounces → \$ 8 cm 3 x (19.3g/cm 3 ) x (1 troy ounce/31.1 g) x \$472/troy ounce = \$2343 21 Convert 251 min m into s μm . A. 4.18 x 10 -6 μm/s B. 1.51 x 10 10 μm/s C. 4.18 x 10 12 μm/s D. 1.51 x 10 -2 μm/s E . 4.18 x 10 6 μm/s Plan: m → μm; min → sec 251 m/min x (1 μm/10 -6 m) x (1 min/60 sec) = 4.18 x 10 6 μm/s 3

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
25 Diamonds have a density of 288 ct/in 3 . What is that density in g/cm 3 ? 1 carat = 0.200g, 1 in. = 2.54 cm (exactly) A. 0.285 g/cm 3 B. 22.6 g/cm 3 C. 17.6 g/cm 3 D. 0.146 g/cm 3 E . 3.51 g/cm 3 (288 ct/in 3 ) x (0.200g/ct) x ((1in) 3 )/((2.54cm) 3 ) = 3.51 g/cm 3 24 Which of the following is not a fundamental unit of SI? A. kg B . L C. mol D. m E. K kg, mol, m and K are all SI units. A dm 3 is called a liter, but neither dm nor L is an SI unit. 4
15 Pressure is force/area. The SI unit for force is kg × m × s -2 . Express pressure in terms of base SI units. A . kg m -1 s -2 B. kg m 2 s -2 C. kg m s -2 D. kg m -2 s -2 E. kg m -3 s -2 Area would have units of m 2 . Pressure = (kg x m x s -2 )/m 2 = kgs -2 /m = kgm -1 s -2 11 Which prefix is correctly associated with its power of ten? A. m 10 -6 B. M 10 3 C. μ 10 -9 D . G 10 9 E. p 10 -15 m = milli = 10 -3 M = mega = 10 6 μ = micro = 10 -6 G = giga = 10 9 p = pico = 10 -12 5

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
2 Convert 55.6 ° F to kelvins. A. 13.1 K B . 286.3 K C. 315.7 K D. 341.3 K E. 68.1 K C o = (5/9)(F-32) = (5/9)(55.6-32) = 13.11 K = 273 + C o = 273 + 13.11 = 286.11 11. The density of a diamond is 3.51 g/cm 3 and 1 carat = 0.200 g. The mass of a diamond whose volume is 2.8 mL is A. 4.0 carats B. 2.0 carats C . 49 carats D. choose this choice if none of the others is correct E. 170 carats 1 cm 3 = 1 mL Begin with what you know, and end with what you’re trying to find. 2.8 mL x (1 cm 3 /1 mL) x (3.51 g/cm 3 ) x (1 carat/0.200 g) = 49.1 carats 25. Given that 1 inch = 2.54 cm and that 1 L = 1000 cm 3 convert 0.092 ft 3 to liters A. 3.2 x 10 -3 L B. 26 L C. 0.40 L D. 1.8 L E . 2.6 L Plan: ft 3 → in 3 → cm 3 → L 0.092 ft 3 x (12 in/1 ft) 3 x (2.54 cm/in) 3 x (1 L/1000 cm 3 ) = 2.605 L 6
2 Convert 55.6 ° F to kelvins. A. 13.1 K B . 286.3 K C. 315.7 K D. 341.3 K E. 68.1 K C o = (5/9)(F-32) = (5/9)(55.6-32) = 13.11 K = 273 + C o = 273 + 13.11 = 286.11 11 Which prefix is correctly associated with its power of ten? A. m 10 -6 B. M 10 3 C. μ 10 -9 D . G 10 9 E. p 10 -15 m = milli = 10 -3 M = mega = 10 6 μ = micro = 10 -6 G = giga = 10 9 p = pico = 10 -12 7

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
15 Pressure is force/area. The SI unit for force is kg × m × s -2 . Express pressure in terms of base SI units.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 29

Chem 161-2010 Tavss' practice problems H&amp;P chapter...

This preview shows document pages 1 - 9. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online