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HW5.E40.Aut2011

HW5.E40.Aut2011 - t = 0.2 μ s and is “going positive”...

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E40 Autumn 2011 Homework 5 Due 5:00 pm, Wednesday, November 9, 2011 Please write your Name and Lab Section Time on the front page. 1. The voltage waveform v s ( t ) steps down at t = 0. (a) What is i R ( t = 0 - ) in mA? What is i R ( t = 0 + ) in mA? (b) What is v R ( t = 0 + ) in Volts? What is v R ( t ) in Volts? (c) Plot v R ( t ) for t 0. (d) Plot v L ( t )for t 0. 2. Find the rms current for this pulse train. 3. A sinusoidal voltage source is zero at
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Unformatted text preview: t = 0.2 μ s and is “going positive” at that point, meaning that v ( t’ ) > 0 for t ’ = 0.21 μ s. Furthermore, the voltage at t = 0 is -28 mV and its next zero is at t = 8.2 μ s. (a) What is the frequency of the voltage source in kHz? (b) Write the expression for v ( t ), as a cosine. 4. U&M 5.30. 5. U&M 7.11 (d) and (e) 6. U&M 7.15 (b) and (f) 7. U&M 7.21...
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