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Unformatted text preview: Segmentation fault – when you try to access a portion of memory when you’re not allowed to. Not allow to touch other ppl’s process. “instantaneous” throughput at time t is w(t)/RTT, almost assuming RTT is infinitesimal If TCP is working the window size can normally increase by one full size packet for every RTT. MTU- maximum transmission unit, size of the max packet of the network TCP: When there’s a loss the window size goes to “1/2”, actually goes to 0 but exponentially increases so say its ½ What determines your throughput when you do a file transfer. Function of throughput Can say there is some average window size W T=avg throughput = W / RTT Rate at which w increases = rate at which W decreases MTU/RTT rate at which it increases = (W / 2 ) x (T/MTU) x p = (W /2) * (W / RTT) *(1/MTU)*p W = sqrt(2/p) T=(MTU/RTT) * sqrt(2/p)...
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This note was uploaded on 11/02/2011 for the course ECE 158a taught by Professor Cruz during the Spring '11 term at UCSD.
- Spring '11