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Unformatted text preview: Segmentation fault – when you try to access a portion of memory when you’re not allowed to. Not allow to touch other ppl’s process. “instantaneous” throughput at time t is w(t)/RTT, almost assuming RTT is infinitesimal If TCP is working the window size can normally increase by one full size packet for every RTT. MTU maximum transmission unit, size of the max packet of the network TCP: When there’s a loss the window size goes to “1/2”, actually goes to 0 but exponentially increases so say its ½ What determines your throughput when you do a file transfer. Function of throughput Can say there is some average window size W T=avg throughput = W / RTT Rate at which w increases = rate at which W decreases MTU/RTT rate at which it increases = (W / 2 ) x (T/MTU) x p = (W /2) * (W / RTT) *(1/MTU)*p W = sqrt(2/p) T=(MTU/RTT) * sqrt(2/p)...
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This note was uploaded on 11/02/2011 for the course ECE 158a taught by Professor Cruz during the Spring '11 term at UCSD.
 Spring '11
 Cruz

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