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# 3 - 3.2 1 3F=X5111X EX2:1 —Y= X4 5111KEX43I-x fEX...

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Unformatted text preview: 3.2 1 3F=X5111X_ EX2 :1 —Y= X4+5111KEX43I -x fEX) =111(11x) 1 f “(le = E (Simplify _]11X 5’ X12 d};_ 1-12111X E‘ T 3?: 111 (TXE- 5x+3]l l_ 14x—5 Y TXE-Sx+3 1551-4 fﬁx}=]11[ ] x f“ 3x4+4 X: X{X4—4:I glix)=exlnxg J 92:“ g(x)= +9e'xhlx x f(x)=]11{29x+7) 9:: f' = S' ]i (x) ggmtunp glixj= ﬂux)” 11 ETX) = 12(111X) Find the equation ofthe line tangent to the graph of f(x) = ﬂux)5 at x: 3. y= 2.43x- 5.68 N(a) =24oo + 45o 111 a Where N(a) is the number ofunits sold, a is the amount spent on advertising, in thousands dollars, and a 2 1. a} How many units were sold after spending \$1,000 on advertising? 2400 units were sold after spending \$1,000 on advertising. in Find N'(a). “a?” T Find N'(10). N '(10) = 45 units per \$1,000 spent on advertising (Simplify your answer.) 0} Find the maximum value, if it exists. Select the correct choice belov:r and ﬁll in any answer boxes within your choice. The maximum value is units. '4' There is no maximum value. Find the minimum value, if it exists. Select the correct choice below and ﬁll in any answer boxes within your choice. " The minimum value is 2400 units. '.here is no minimum value. [1} Find .im N '(a). Does it make sense to spend more and more dollars on advertising? a )3: 5’ lim N '(a) = 0, so it does not make sense. Eventually, the proﬁt from the increase it a Mn sacs will be less than the amount spent on advertising to achieve that increase. lim N “(3) =450, so it does make sense. The derivative is always positive as a a Mn increases, so the sales, and consequently proﬁt, will continually increase. ...
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