Chapter9 - CHE141 Chapter 9 Chapter 9 Molecular Geometry...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
CHE141 Chapter 9 Copyright © 2006 Dr. Harshavardhan D. Bapat 1 Chapter 9 Molecular Geometry and Bonding Theories 1. For a molecule with the formula AB 2 the molecular shape is __________. (a). linear or trigonal planar (b). linear or bent (c). linear or T-shaped (d). T-shaped Explanation: When answering questions like these always try to imagine a molecule that would fit the generic (AB 2 ) formula. In this case you could use the examples of CO 2 or H 2 O. Thus in the case of CO 2 , the molecule would be linear since the central atom would not have any lone pairs while with water the shape would be bent due to the lone pairs on the central atom. 2. According to VSEPR theory, if there are five electron domains in the valence shell of an atom, they will be arranged in a(n) __________ geometry. (a). octahedral (b). trigonal bipyramidal (c). tetrahedral (d). trigonal planar Explanation: The trigonal bipyramidal arrangement of electron domains would be the ideal one to minimize the repulsions involved. 3. The electron-domain geometry and molecular geometry of iodine trichloride are __________ and __________ respectively. (a). trigonal bipyramidal, trigonal planar (b). tetrahedral, trigonal pyramidal (c). trigonal bipyramidal, T-shaped (d). octahedral, trigonal planar Explanation: The Lewis structure of ICl 3 shows that the two lone pairs occupy the equatorial positions in this trigonal bipyramidal electron domain geometry. The molecule itself is T-shaped. The lone pairs occupy equatorial positions and are 120° apart, experiencing the least amount of repulsions, compared to axial positions. Cl I Cl Cl
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
CHE141 Chapter 9 Copyright © 2006 Dr. Harshavardhan D. Bapat 2 4. According to valence bond theory, which orbitals on bromine atoms overlap in the formation of the bond in Br 2 ? (a). 3s (b). 3p (c). 4s (d). 4p Explanation: According to the valence bond theory, orbital overlap between two atoms leads to a bond formation. The orbitals that overlap are usually the outermost valence orbitals. In Br atoms, the valence electrons are held in the 4s and 4p orbitals with the 4p being the outermost orbital. 5. The electron-domain geometry of a sulfur-centered compound is trigonal bipyramidal. The hybridization of the central sulfur atom is __________. (a). sp (b). sp 2 (c). sp 3 d (d). sp 3 Explanation: A trigonal bipyramidal electron domain geometry indicates that there are 5 electron domains available. These 5 electron domains can be made possible only if a sp 3 d set of hybrid orbitals is available on the central atom. 6. The hybridization of orbitals on the central atom in a molecule is sp. The electron- domain geometry around this central atom is __________.
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This document was uploaded on 11/03/2011 for the course CH 101 at Montgomery College.

Page1 / 12

Chapter9 - CHE141 Chapter 9 Chapter 9 Molecular Geometry...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online