Unformatted text preview: set the KE of each gas equal to each other like so: KE H2O = KE CO2 Hopefully you remember that KE = 1/2mv 2 . We can now adjust the formula to 1/2m H2O (v H2O ) 2 = 1/2m CO2 (v CO2 ) 2 Now you can use algebra to rearrange the formula so it equals the ratio we are looking for. Our formula now looks like this: v H2O /v CO2 = √(m CO2 /m H2O ). Substituting the molar masses of CO 2 and H 2 O into the equation, we get: v H2O /v CO2 = √44/18 = 1.6/1. In other words, v H2O = 1.6 when v CO2 =1. That means water diffuses 1.6 times faster than carbon dioxide. ....
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- Fall '08