Unformatted text preview: where x is the unknown weight of solution. Thus x = 180,000 g We assume that the weight of water is so much greater than the weight of glucose in the solution that we can use the weight of the solution as the weight of water, especially given the small number of significant digits being used. This assumption also implies that the density of the solution is approximately that of pure water, meaning that the volume of the solution is 180 L, good to 2 significant digits at least. FUN!...
View
Full Document
 Fall '08
 Herron,S
 Glucose, Mass, Kilogram

Click to edit the document details