problem29_73

# problem29_73 - 29.73 a G(0 r cm m g summed over each leg m...

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29.73: a) , g r τ m cm G × = summed over each leg, ) 90 sin( 4 2 ) 90 sin( 4 2 ) 90 sin( 4 ) 0 ( φ φ φ - + - + - = g m L g m L g m ) 90 sin( 4 ) ( φ - + g m L ). (clockwise cos 2 φ mgL = φ sin IAB B = × = B μ τ (counterclockwise). . sin sin cos φ ϖ φ φ φ ε R BA dt d R BA dt d R BA R I = - = = = The current is going counterclockwise looking to the k ˆ - direction. , sin sin 2 4 2 2 2 2 φ ϖ φ ϖ τ R L B R A B B = = , sin cos 2 so 2 4 2 φ ϖ φ τ R L B mgL - = opposite to the direction of the rotation. b) α I τ = ( I being the moment of inertia).

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