EAS207-1st-exam-sol-2007

EAS207-1st-exam-sol- - EAS 207 FALL 2007 TEST#1 Friday October 51th 7-8:50 pm J‘Emalf/y/l MM Note a Closed book formula sheet given b Present

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Unformatted text preview: EAS 207 FALL 2007 TEST #1 Friday, October 51th 7-8:50 pm J‘Emalf/y/l/ MM Note: a) Closed book, formula sheet given. b) Present your answers in the “blue book provided. c) Be sure your name, printed clearly, is on the “blue book” and the other infomation is provided. _ d) No book bags, cell phones or anything else besides drafting tools, calculator and pencils. (10 pts.) 1. For the system shown below, OA is a horizontal, 12 ft. long rigid strut, BA » and CA are cables, 0 is a ball—and—socket joint. A 1,000 lb. load is acting downward at A. Assume the xyz axis system is as shown with y upward and the cables are attached to the yz plane at B and C. The tensile force in cable AB is 900 lb. and the compressive force in 0A is 1000 lb. Determine: a) The force in cable AC b) The position 0, y, z) where cable AC is attached to the yz plane. Bf” / ’” 6/0, /4, /Z) -’ / V/z {ya/4 gag—1 M— 5 it C7 Z’Z \l—‘V ‘ g0! ~* :3,» : —~.-r4n; . a! may; - ' v .1 V v ,5: i Q . ’-)aaesi.~4yo a any 7e 4949 ii 69: flatan ah: - ,._.. .- -,6/72 7». 5/7/ ~. 52°32 Ac: , g (F) . -‘ - . . D9 ‘ «mg-W -— 50M lg=ffrfio 14—? 2550 "V/ a _ was i r M '/?=J_foa $6331]? 8 y We 1? =2} =zoo+£20g: ({33 \ H, .. z :V 2 a - xv t9=€ "557 ~a a“ if? I! I I 7‘ ' ,K as \L’” lilzffi ‘ 5/V w A :9 “49° /i»3\ ~,~ , i * e ‘ y mi” Riff Me o/a 67%,? flare <7) KN;//flf V}? V Z%=600'2006453' J§9K7jvioo (4/):- 2/5 ’V’”. (8 pts.) 2. Three forces and a couple are applied to a bracket as shown below. Determine a) The magnitude and direction of the resultant, R. Plot the vector R. b) The perpendicular distance, dR, and the x intercept, XR, from point 0 to the line of action of R. Sketch your answer accurately on the figure. fecfioz film“ 500 N ,V a '7" “‘"* N f. 1“ ‘- 00 i he C9560 1» 3): VJ E2 i: l l" 2 j. «a» gao :uméa} i g l‘ l A } re———45U mm wife—450 mm ~——+l ‘9 r :20; afd/e' “2/5= 5' 12 83,9 26%“ 0g; 2.55m”? \—-> 12%: A2 223/ $3127" /7 .\ i z 1’? , " A7 . E f‘ g g E \. \i Y‘gcx E—too K) + TBLX Us"? +§§+E© w’} :55 i f»; (10 pts.) 3. Each of the two legs of the welded frame weighs 100 lbs. A’wire from C to c.‘ D prevents the frame from rotating out of the horizontal plane bout an axis through its bearing at B and its ball-and-socket joint at A. Cal ulate the tension T in the wire and the magnitude of the total force supported by the connection at A. Note: At B there can only be reaction components in the x and 2 directions and no moments. 0 .:zy‘/(’2):7;/2) 7: " ZK/ r 2&0 /5 if" ‘m?g~;~mwwww. I. ‘ {v g “h v- 24 kwtmm ' 3/6 1:; 315mg): 0 4, (a) = W) 1W) — 7E6?) —- m— 400 42 '“" 5—0 M- 47 :- 55: [£9 .,...~g .- , _ X ,5 I t g s I ’ 5 ,3} «' \ _, A.) A " (“of {WK}; far We aim wt; 6 .: /Z_Z ' A ”‘ ' n“. k '3’ PM W mm»m».....m- m.” m a V *‘ Won-memn V k :1, -0408”? ,04083; +0~szm A A -An fiA-O'cg‘éTk T , _. ,. . 8T 1 OW 3 E , A K Ix 9 Mzoowrfl , _ e—x ==> “33¢ +R>< "0'408T”O ~ A 5 f" ~<8Ex V —“\- E? 532 4“ +2003 "€00 ‘ .’\ 3“ A +4.g%er?+my—zom=; .— 06321'4} 41,4481 k 3E2 Loo -\'C>3ZTV"“Z°° 7' O 1—600 +4‘K96T “200 2 @ ’62qu 7; <3 "'~' "* A P" ><(~\OOK+?) ’— - 1+82V>+ Y9” Mpf XfiBXC x ’— -\00v< ‘20 + me C > A 4‘ ’5 _ ’h 25 fig:- ) YfiLZZfi +g§3T35~21+23 R __ <g§ xkgxfik‘gzfi) +£2f+6j)x(-\00Y~) %’ > r“ 5 ix ‘ ‘ +05? +6§)xC—0-408T« ~0408T3 +0-816Tk) 3x— CZ?+Z§>XC~%QOK) :Q /\ )ETK' 1 5 x r i v a E i 0 fig) i i —/’© : flgggy .. o rgxe'T +2'4\“W: 00 = 2454‘» FYOM Tzégp’ V/wf F‘mm' 82'; “SO 1475 Fm ear/£47 'finvz: mo 3 ...
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This document was uploaded on 11/04/2011 for the course EAS 207 at SUNY Buffalo.

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EAS207-1st-exam-sol- - EAS 207 FALL 2007 TEST#1 Friday October 51th 7-8:50 pm J‘Emalf/y/l MM Note a Closed book formula sheet given b Present

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