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EAS207-1st-exam-sol-2010

# EAS207-1st-exam-sol-2010 - Q EAS 20" STATl‘CS First...

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Unformatted text preview: Q) EAS 20"? - STATl‘CS First Exam Fall 2010 Total points: 100 Time: 2 hours Notes: Closed book exam. Q.1) Replace the forces shown in Fig. 1 by an equivalent force system at point 0. Then reduce the equivalent force system at O to a Wrench force system and locate the intersection of the wrench with the xy—plane. Use vectors for your moment and force calculations. (33 points) M g? R O Q 39 W WMwWMW ‘ V A m . W“ E“ «z 2 f «- " WM m M ﬂMe—wmwwm"w—~-~«~1~-~-~~—mam-WWMMMMWMWNMM \@ M ” K ' 5 géoz“ a] M“ : MOrM? FwaééB1+ J jmmllikkw} WM,.W.... w (1 “(EX E6); Z MY) , (x? + 9 § 3x (449,4 T + €8£6 g“ #473, ék) h :2 «mac; )9 3+ QéDZj M034 K, @y Q..2) A bracket is subjected to 3 forces and 2 moments as shown in Fig.2. Replace the given forces system by an equivalent force system at point A. Then find the points of intersection of the simplest resultant with x and y axes. F1: 15% , «f \ (33 points) 5““ , ER": ,_ V303- ﬁgwgogy, ,2 45o llgs ’5“ ”(H 1"” 'ZFa ~ also _. ago—3% :~i§o~izo:-3:7_olm ‘ ‘“ ._, ~l§o 1.2703? (tbs); Fl; ”— \ , Q 2‘ Q.3) Draw free-body diagram(s) for the loaded frame shown in Fig. 3. The C/ radius of the disc at D is 1 foot and its weight is 300 lbs. The weight hanging from the disc is 500 lbs. Find the reaction forces at supports A and B. (34 points) @va #3 CM: {mm i @01226 970 ”1/ c J . 1 \ \$3520”??? VCSW‘WOO ”5) m 4 4‘7?- E: + o 5709 F; «1390 ngoo :0 5‘ :43 \$124500 PC":- 875 MO)w K’@ RQC‘AC/qum 03? P: [25%; gTSWM :2 \$75“ (1,0301 :2 “732,65 Kiss Ha :‘876 \$mo< 2* BMAM M {33% ﬁr FéCObOL 3 0 g wmgmszesfﬁngrém Né: “33‘8“ \\A&\C0§€A *qujiykﬁ/ Cat‘s‘smemg EX £23 wwmﬁa. \Bx: "7826 //‘U>§’O 8d A75 gmcx R300 500 :0 ”’ WMA M73 8 z: 800%“ @733ka M B :Mmm r6) ...
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