Class Examples for Chapter 28

Class Examples for Chapter 28 - Class Examples for Chapter...

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1 Class Examples for Chapter 28 11. Since the total force given by F e E v B d i vanishes, the electric field E must be perpendicular to both the particle velocity v and the magnetic field B . The magnetic field is perpendicular to the velocity, so v B has magnitude vB and the magnitude of the electric field is given by E = vB . Since the particle has charge e and is accelerated through a potential difference V , 2 / 2 mv eV and 2 . v eV m Thus,  19 3 5 27 2 1.60 10 C 10 10 V 2 1.2 T 6.8 10 V m. 9.99 10 kg eV E B m 20. Combining Eq. 28-16 with energy conservation ( eV = 1 2 m e v 2 in this particular application) leads to the expression r = m e e B 2 eV m e which suggests that the slope of the r versus V graph should be 2 2 / e m eB . From Fig. 28-39, we estimate the slope to be 5 10 5 in SI units. Setting this equal to 2 2 / e m eB and solving we find B = 6.7 10 2 T.
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