problem29_75

problem29_75 - resistance. Therefore the potential...

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29.75: a) b) The induced emf on the side ac is zero, because the electric field is always perpendicular to the line . ac c) To calculate the total emf in the loop, dt dB L dt dB A dt d B 2 = = Φ = ε V. 10 1.40 ) s T 035 . 0 ( m) 20 . 0 ( 3 2 - × = = ε d) A. 10 37 . 7 90 . 1 V 10 40 . 1 4 3 - - × = × = = R I e) Since the loop is uniform, the resistance in length ac is one quarter of the total
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Unformatted text preview: resistance. Therefore the potential difference between a and c is: V, 10 3.50 ) 4 A)(1.90 10 37 . 7 ( 4 4-ac ac IR V = = =-and the point a is at a higher potential since the current is flowing from c. to a...
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