Molecular Weight Determination of an Unknown Acid

Molecular Weight Determination of an Unknown Acid -...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Molecular Weight Determination of an Unknown Acid Olivia Downs 2/14/11 CHM 1046L / #85606
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
The purpose of this experiment is to determine the molecular weight of an unknown acid through four trials of titration. Unknown acid: D Mono-, Di-, or Triprotic: Diprotic Molarity of NaOH: .09664 M Titration Trials of the Unknown Acid Trial 1 Trial 2 Trial 3 Trial 4 Mass of Acid (g) .2176 g .2105 g .2169 g .2176 g Final Vol NaOH (mL) 33 mL 40 mL 35.2 mL 35.5 mL Initial Vol NaOH (mL) 1.50 mL 1.00 mL 3.10 mL 1.50 mL Total Vol NaOH (mL) 31.5 mL 39.0 mL 32.1 mL 34.0 mL Comments: Purple/pink Same color Same color Same color The balanced equation of the titration reaction was: H2A + 2NaOH -> Na2A + 2H2O. Sample calculation for Trial #1: Moles of NaOH: .09664 M NaOH × .0315 L = .00304 moles NaOH Moles of acid: .00304 mol NaOH ÷ 2 mol NaOH × 1 mol acid = .00152 moles acid MW of acid: .2176 g acid÷ .00152 mol acid = 143 g/mol acid Calculation Summary of the Titration Trials Trial 1 Trial 2 Trial 3 Trial 4
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 3

Molecular Weight Determination of an Unknown Acid -...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online