PracticeSheet3 key (1)

PracticeSheet3 key (1) - 34 18 --= 8.54 10 15 Hz b) = c =...

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Practice Sheet 3 3B.1 Radio waves < microwaves < infrared light < x-rays < gamma rays. There is an inverse relationship between wavelength and energy (i.e., the longer the wavelength, the lower the energy, and vice versa). There is an inverse relationship between wavelength and frequency. 3B.2 λ 1/ ν so ν 2 = λ 1 = 67 nm = 1.29 ν 1 λ 2 52 nm 3B.3 Green is higher energy and therefore must be the shorter wavelength, 500nm. 3D.1 E = λ hc = m 10 6.34 m/s) 10 s)(2.9979 J 10 (6.626 9 8 34 - - × × × = 3.13 × 10 –17 J/photon We now need to convert J/photon to kJ/mol of photons. × × - J 1000 kJ 1 photons mol 1 photons 10 6.022 photon 1 J 10 3.13 23 17 = 1.89 × 10 4 kJ/mol photons 3D.2 a) ν = h E = s J 10 6.626 J 10 5.66
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Unformatted text preview: 34 18 --= 8.54 10 15 Hz b) = c = Hz 10 8.54 m/s 10 9979 . 2 15 8 = 3.51 10-8 m 3D.3 (a) wavelength is 10 cm (b) 1/2 x 10 = 5 cm (c) 4 waves, 7 nodes 3D.4 The ratio of energies will be the same when comparing one photon to another as when comparing one mole of photons to one mole of the other. For the first photon, E 1 = hc = nm 10 4.00 hc 2 = 4.97 10-19 J / photon For the second photon, E 2 = h = h (2.45 10 9 s 1 ) = 1.62 10-24 J / photo Next, E 1 /E 2 = 4.97 10-19 J / photon = 3.07 10 5 1.62 10-24 J / photon Thus, E 1 is larger than E 2 by a factor of 307,000 times....
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