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Unformatted text preview: b) c) d) e) C H H H H 2-2-2-C O O O C O O O C O O O N Cl Cl Cl C N H 7D.6 Magnesium nitrate is Mg(NO 3 ) 2 , so there are 6 O atoms in each Mg(NO 3 ) 2 . So, the calculation is as follows: Mg(NO3)2 Mg(NO3)2 Mg(NO3)2 Mg(NO3)2 mol 0.5 toms O 6 mol 10 x 6.022 23 a = 1.8 10 24 O atoms 7D.7 a) SO 4 2 d) HPO 4 2 b) ClO 2 e) ClO 4 c) OH f) NH 4 +...
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This note was uploaded on 11/04/2011 for the course CHEM 105 taught by Professor Macedone during the Fall '07 term at BYU.
- Fall '07