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Unformatted text preview: C p = (USLS)/6 σ = (100.599.5)/(6x0.414) = 0.40; Not capable because C p < 1. C pk = Min{(US)/3 σ, (LS)/3 σ} = Min{(100.599.765)/(3x0.414), (99.76599.5)/(3x0.414)} = 0.725; Not capable because C pk < 1. Since C p < 1, the variability (std. dev.) must be reduced. Further, the mean must be increased, since C pk < 1. 4a. A pchart should be used because control limits are required for the proportion of wrong reports. Also, the sample size and # defective are given. b. = 20/2000 = 0.01, n = 200, z = 3 = = 0.007 UCL = + z σ = 0.01 + (3x0.007) = 0.031 LCL =  z σ = 0.01 – (3x0.007) = 0.011 → 0 c. Sample p 1 1/200 = 0.005 2 3/200 = 0.015 3 3/200 = 0.015 4 5/200 = 0.025 5 2/200 = 0.01 All 5 samples (100%) lie between control limits. We need at least 99.7% with 3sigma limits, so the process is in control....
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This note was uploaded on 11/04/2011 for the course DS 412 taught by Professor Eng during the Fall '07 term at S.F. State.
 Fall '07
 Eng

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