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Unformatted text preview: C p = (USLS)/6 σ = (100.599.5)/(6x0.414) = 0.40; Not capable because C p < 1. C pk = Min{(US)/3 σ, (LS)/3 σ} = Min{(100.599.765)/(3x0.414), (99.76599.5)/(3x0.414)} = 0.725; Not capable because C pk < 1. Since C p < 1, the variability (std. dev.) must be reduced. Further, the mean must be increased, since C pk < 1. 4a. A pchart should be used because control limits are required for the proportion of wrong reports. Also, the sample size and # defective are given. b. = 30/1500 = 0.02, n = 150, z = 2 = = 0.0114 UCL = + z σ = 0.02 + (2x0.0114) = 0.0428 LCL =  z σ = 0.02 – (2x0.0114) = 0.0028 → 0 c. Sample p 1 2/150 = 0.0133 2 0/150 = 0 3 6/150 = 0.04 4 3/150 = 0.02 5 1/150 = 0.0067 All 5 samples (100%) lie between control limits. We need at least 95.5% with 2sigma limits, so the process is in control....
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 Fall '07
 Eng
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