{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

In our metapopulation example above

In our metapopulation example above - In our metapopulation...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
In our metapopulation example above, on the left all demes have p = 0.5 and the allele frequency for the entire array is also p = 0.5. Right away you can se that there in no differentiation among demes. To quantify this we use Fst which is calculated as Fst = (Ht - mean Hs) / Ht , where Ht = 2 (pooled p) (pooled q) [note that pooled q = (1-pooled p)], and mean Hs = the average of H values for each of the individual demes (i.e., 2 p q for each deme, averaged across all demes). For the left-hand metapopulation Ht = 2(0.5)(0.5) = 0.5, and mean Hs = 0.5 also. Thus , Fst = (0.5 - 0.5) / 0.5 = 0.0. What does this mean? In English this says that none of the variation in this system of demes lies between demes; the population structure is zero. Since there is variation (i.e., p _ 0) all of the variation lies within demes. Now consider the metapopulation system on the right above. The pooled allele frequency is 0.5 because half of the demes are fixed for the A allele (p = 1.0) and half are fixed for the a allele (p = 0.0). Hence the Ht value is 2 (pooled p) (pooled q) = 2(0.5)(0.5) = 0.5. The m e an Hs value is very different. Each deme has a heterozygosity
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online