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Unformatted text preview: a paralyzed fly. In this case a true breeding paralyzed fly would have genotype: aaaaa / aaaaa , bbbbb / b Whereas wild type would have genotype: AAAAA / AAAAA , BBBBB / B F1: AAAAA / aaaaaBBBBB / b not paralyzed F2: p( aaaaa / aaaaa and bbbbb / bbbbb ) = ( 1/ 4 ) 2 = 1 /16 p( aaaaa / aaaaa and BBBBB / ) = 1 /4 x 3 /4 = 3 /16 p( bbbbb / bbbbb and AAAAA / ) = 3 /16 p( AAAAA / and BBBBB / ) = the rest = 9 /16 This is the classic ratio for two gene segregation 9 : 3 : 3 : 1 paralyzed...
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This note was uploaded on 11/05/2011 for the course BIOLOGY MCB2010 taught by Professor Jessicadigirolamo during the Fall '10 term at Broward College.
- Fall '10